5(2^x-1)=10(^2x-3)

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Solution for 5(2^x-1)=10(^2x-3) equation: 



5(2^x-1)=10(^2x-3)

We move all terms to the left:

5(2^x-1)-(10(^2x-3))=0

We multiply parentheses

10x-(10(^2x-3))-5=0



We calculate terms in parentheses: -(10(^2x-3)), so:

10(^2x-3)

We multiply parentheses

10x-30

Back to the equation:

-(10x-30)



We get rid of parentheses

10x-10x+30-5=0

We add all the numbers together, and all the variables

25!=0

There is no solution for this equation

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